Hacker News new | past | comments | ask | show | jobs | submit login

It's funny how much of physics we do assuming a flat earth.

If you did it "properly" you would calculate the orbit of the brick (assuming earth was a point mass), then find the intersection between that orbit and earth's surface. But for small speeds and distances you can just assume g points down as it would in a flat earth




To do it properly you have to account for the gravitational pull of the building.




Consider applying for YC's Spring batch! Applications are open till Feb 11.

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: